TSTP Solution File: SEV160^5 by cocATP---0.2.0

View Problem - Process Solution

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% File     : cocATP---0.2.0
% Problem  : SEV160^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n095.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:49 EDT 2014

% Result   : Theorem 0.42s
% Output   : Proof 0.42s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
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%----ERROR: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEV160^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n095.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 08:16:21 CDT 2014
% % CPUTime  : 0.42 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x259e680>, <kernel.Type object at 0x259ef38>) of role type named a_type
% Using role type
% Declaring a:Type
% FOF formula (<kernel.Constant object at 0x259eab8>, <kernel.Constant object at 0x259e518>) of role type named y
% Using role type
% Declaring y:a
% FOF formula (<kernel.Constant object at 0x246ccf8>, <kernel.Constant object at 0x259e518>) of role type named x
% Using role type
% Declaring x:a
% FOF formula (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) of role conjecture named cTHM186_pme
% Conjecture to prove = (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))):Prop
% We need to prove ['(((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))']
% Parameter a:Type.
% Parameter y:a.
% Parameter x:a.
% Trying to prove (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Found eta_expansion000:=(eta_expansion00 (fun (Xg:(a->(a->a)))=> ((Xg x) y))):(((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (x0:(a->(a->a)))=> ((x0 x) y)))
% Found (eta_expansion00 (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Found ((eta_expansion0 a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Found (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Found (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Got proof (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Time elapsed = 0.115466s
% node=11 cost=-282.000000 depth=3
% ::::::::::::::::::::::
% % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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