TSTP Solution File: SEV160^5 by cocATP---0.2.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : SEV160^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n095.star.cs.uiowa.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory : 32286.75MB
% OS : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:33:49 EDT 2014
% Result : Theorem 0.42s
% Output : Proof 0.42s
% Verified :
% SZS Type : None (Parsing solution fails)
% Syntax : Number of formulae : 0
% Comments :
%------------------------------------------------------------------------------
%----ERROR: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem : SEV160^5 : TPTP v6.1.0. Released v4.0.0.
% % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n095.star.cs.uiowa.edu
% % Model : x86_64 x86_64
% % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory : 32286.75MB
% % OS : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 08:16:21 CDT 2014
% % CPUTime : 0.42
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x259e680>, <kernel.Type object at 0x259ef38>) of role type named a_type
% Using role type
% Declaring a:Type
% FOF formula (<kernel.Constant object at 0x259eab8>, <kernel.Constant object at 0x259e518>) of role type named y
% Using role type
% Declaring y:a
% FOF formula (<kernel.Constant object at 0x246ccf8>, <kernel.Constant object at 0x259e518>) of role type named x
% Using role type
% Declaring x:a
% FOF formula (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) of role conjecture named cTHM186_pme
% Conjecture to prove = (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y))):Prop
% We need to prove ['(((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))']
% Parameter a:Type.
% Parameter y:a.
% Parameter x:a.
% Trying to prove (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Found eta_expansion000:=(eta_expansion00 (fun (Xg:(a->(a->a)))=> ((Xg x) y))):(((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (x0:(a->(a->a)))=> ((x0 x) y)))
% Found (eta_expansion00 (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Found ((eta_expansion0 a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Found (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Found (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) as proof of (((eq ((a->(a->a))->a)) (fun (Xg:(a->(a->a)))=> ((Xg x) y))) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Got proof (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% Time elapsed = 0.115466s
% node=11 cost=-282.000000 depth=3
% ::::::::::::::::::::::
% % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% (((eta_expansion (a->(a->a))) a) (fun (Xg:(a->(a->a)))=> ((Xg x) y)))
% % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
%------------------------------------------------------------------------------